Estimating Timing

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We want to estimate the required acceleration time period.

Timing

Gratuitous stopwatch This crude approximation will confirm if the LC timing estimates are in the appropriate range.

Assume:

Solution:

  1. Distance d = at2/2
    Solving this for t yields: t = sqrt(2d/a)
  2. Also, from classical physics, we know v = at
    Solving this for a yields: a = v/t

Put 1) and 2) together to get: t = 2d/v

At 50 fps:

At 200 fps:

This means that a current pulse between 1 and 7 milliseconds is necessary to match the required acceleration time.

This timing does fit well into the energy calculations used elsewhere.


Last update June 25, 2007 by Barry Hansen ©2007